Home > Numerical methods calculators > Numerical Interpolation using Forward, Backward, Divided Difference, Langrange's Interpolation method calculator

Method and examples
Numerical Interpolation using
Forward, Backward, Divided Difference, Langrange's Interpolation Method
Method

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1.  x 0 1 2 3 f(x) 1 0 1 10
and x=4
2.  x 0.1 0.2 0.3 0.4 0.5 f(x) 20.025 10.0501 6.74211 5.10105 4.12706
and x=0.15
3.  x 1891 1901 1911 1921 1931 f(x) 46 66 81 93 101
and x=1895
4.  x 1891 1901 1911 1921 1931 f(x) 46 66 81 93 101
and x=1925
5.  x 3 4 5 6 7 8 9 f(x) 2.7 6.4 12.5 21.6 34.3 51.2 72.9
and x=1
6.  x 3 4 5 6 7 8 9 f(x) 2.7 6.4 12.5 21.6 34.3 51.2 72.9
and x=10
7.  x 10 15 20 25 30 f(x) 0.1003 0.1511 0.227 0.2553 0.3093
and x=12
8.  x 10 15 20 25 30 f(x) 0.1003 0.1511 0.227 0.2553 0.3093
and x=40
9.  x 300 304 305 307 f(x) 2.4771 2.4829 2.4843 2.4871
and x=301
10.  x 2 2.5 3 f(x) 0.69315 0.91629 1.09861
and x=2.7
11.  x 0 1 3 4 f(x) -12 0 12 24
and x=5
12.  x -1 0 3 6 7 f(x) 3 -6 39 822 1611
and x=8
13.  x 0.2 0.3 0.5 0.7 0.8 f(x) 1.1487 1.23114 1.41421 1.62451 1.7411
and x=0.40
 f(x) = x1 = and x2 = x = Step value (h) =  OR  Inverval (N) = Find  1. Auto select mehtod 2. Forward 3. Backward 4. Divided Difference 5. Langranges Interpolation f(x)=2x^3-4x+1x1 = 2 and x2 = 4x = 3.8Step value (h) = 0.5 or N = 5f(x)=2x^3-4x+1x1 = 2 and x2 = 4x = 2.1Step value (h) = 0.25 or N = 8f(x)=x^3-x+1x1 = 2 and x2 = 4x = 3.8Step value (h) = 0.5 or N = 5f(x)=x^3-x+1x1 = 2 and x2 = 4x = 2.1Step value (h) = 0.25 or N = 8f(x)=x^3+x+2x1 = 2 and x2 = 4x = 3.8Step value (h) = 0.5 or N = 5f(x)=x^3+x+2x1 = 2 and x2 = 4x = 2.1Step value (h) = 0.25 or N = 8f(x)=sin[x]x1 = 0 and x2 = 1.57x = 2Step value (h) = 0.25 or N = 8f(x)=cos[x]x1 = 0 and x2 = 1.57x = 2Step value (h) = 0.25 or N = 8
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