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Numerical Interpolation using Forward, Backward, Divided Difference, Langrange's Interpolation method calculator
Method and examples
Numerical Interpolation using
Forward, Backward, Divided Difference, Langrange's Interpolation Method
Method
1. Find Numerical Interpolation for x & f(x) table data
2. Find Numerical Interpolation for f(x) = x^3+x+2 & step value (h)
Type your data in either horizontal or verical format,
for seperator you can use '-' or ',' or ';' or space or tab
for sample click random button
OR
Rows :
Click On Generate
x =
Find
1. Auto select mehtod
2. Forward
3. Backward
4. Divided Difference
5. Langranges Interpolation
6. Divided Difference Equation
7. Langranges Interpolation Equation
x
0
1
2
3
f(x)
1
0
1
10
and x=4
x
0.1
0.2
0.3
0.4
0.5
f(x)
20.025021
10.050130
6.742110
5.101050
4.127060
and x=0.15
x
1891
1901
1911
1921
1931
f(x)
46
66
81
93
101
and x=1895
x
1891
1901
1911
1921
1931
f(x)
46
66
81
93
101
and x=1925
x
3
4
5
6
7
8
9
f(x)
2.7
6.4
12.5
21.6
34.3
51.2
72.9
and x=1
x
3
4
5
6
7
8
9
f(x)
2.7
6.4
12.5
21.6
34.3
51.2
72.9
and x=10
x
10
15
20
25
30
f(x)
0.1003
0.1511
0.227
0.2553
0.3093
and x=12
x
10
15
20
25
30
f(x)
0.1003
0.1511
0.227
0.2553
0.3093
and x=40
x
300
304
305
307
f(x)
2.4771
2.4829
2.4843
2.4871
and x=301
x
2
2.5
3
f(x)
0.69315
0.91629
1.09861
and x=2.7
x
0
1
3
4
f(x)
-12
0
12
24
and x=5
x
-1
0
3
6
7
f(x)
3
-6
39
822
1611
and x=8
x
0.2
0.3
0.5
0.7
0.8
f(x)
1.148698
1.231144
1.414214
1.624505
1.741101
and x=0.40
f(x) =
x
_{1}
=
and x
_{2}
=
x =
Step value (h) =
OR Inverval (N) =
Find
1. Auto select mehtod
2. Forward
3. Backward
4. Divided Difference
5. Langranges Interpolation
`f(x)=2x^3-4x+1`
x1 = 2 and x2 = 4
x = 3.8
Step value (h) = 0.5
or N = 5
`f(x)=2x^3-4x+1`
x1 = 2 and x2 = 4
x = 2.1
Step value (h) = 0.25
or N = 8
`f(x)=x^3-x+1`
x1 = 2 and x2 = 4
x = 3.8
Step value (h) = 0.5
or N = 5
`f(x)=x^3-x+1`
x1 = 2 and x2 = 4
x = 2.1
Step value (h) = 0.25
or N = 8
`f(x)=x^3+x+2`
x1 = 2 and x2 = 4
x = 3.8
Step value (h) = 0.5
or N = 5
`f(x)=x^3+x+2`
x1 = 2 and x2 = 4
x = 2.1
Step value (h) = 0.25
or N = 8
`f(x)=sin[x]`
x1 = 0 and x2 = 1.57
x = 2
Step value (h) = 0.25
or N = 8
`f(x)=cos[x]`
x1 = 0 and x2 = 1.57
x = 2
Step value (h) = 0.25
or N = 8
Solution
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