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Area 10 of 13
I know that for a rightangle triangles = and = . From this find out of the rightangle triangles.

 
 
SolutionRightangle Triangle FormulaArea Formula
Area of Rightangle Triangle
Diagonal `(d) = sqrt(a^2 + b^2)`
Perimeter `(P) = a+b+c`
Area `(A) = 1/2(a b)`

Example :
I know that for a rightangle triangles AB = 5 and BC = 12 . From this find out Area of the rightangle triangles.

`"Here one Side" = 5" and other Side" = 12" (Given)"`

`"We know that,"`

`"In triangle ABC, by Pythagoras' theorem"`

`AC^2 = AB^2 + BC^2`

`AC^2 = 5^2 + 12^2`

`AC^2 = 25 + 144`

`AC^2 = 169`

`AC = 13`


`"Perimeter" = AB + BC + AC`

` = 5 + 12 + 13`

` = 30`

` `


`"Here base" = 5" and height = "12 `

`"We know that,"`

`"Area" = 1/2 * AB * BC`

` = 1/2 * 5 * 12`

` = 30`


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