Problem: (x^2+1/x^2)-8(x-1/x)+14=0 [ Calculator, Method and examples ]
Solution: Your problem `->` (x^2+1/x^2)-8(x-1/x)+14=0
`1(x^2+1/x^2)-8(x-1/x)+14=0`
Let `x-1/x=m`
`=>(x-1/x)^2=m^2`
`=>x^2+1/x^2-2=m^2`
`=>x^2+1/x^2=m^2 + 2`
Substituting this values in the given equation, we get `(m^2+2)-8m+14=0`
`=>m^2-8m+16=0`
`m^2-8m+16=0`
`=>m^2-8m+16 = 0`
`=>(m)^2 - 2(m)(4) + (4)^2 = 0`
`=>(m-4)^2 = 0`
`=>(m-4) = 0`
`=>m = 4`
Now, `x-1/x=4`
`=>x^2-1=4x`
`=>x^2-4x-1=0`
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Solution provided by AtoZmath.com
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