Boole's rule, 1/x, [1,2], h=0.25

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Problem: Boole's rule, 1/x, [1,2], h=0.25 [ Calculator, Method and examples ]

Solution:
Your problem `->` Boole's rule, 1/x, [1,2], h=0.25

Equation is `f(x)=(1)/(x)`.

Method-1:
The value of table for `x` and `y`

x	1	1.25	1.5	1.75	2
y	1	0.8	0.6667	0.5714	0.5

Using Boole's Rule
`int y dx=(2h)/45 [7(y_0 + y_4)+32(y_1+y_3)+12(y_2)+14()]`

`int y dx=(2xx0.25)/45 [7xx(1 +0.5)+32xx(0.8+0.5714)+12xx(0.6667)+14xx()]`

`int y dx=(2xx0.25)/45 [7xx(1.5) + 32xx(1.3714) + 12xx(0.6667) + 14xx(0)]`

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