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Find 15's complement subtraction B06-C7C

Solution:
Your problem `->` 15's complement subtraction B06-C7C


15's complement subtraction steps :

1. At first, find 15's complement of the B(subtrahend).
2. Then add it to the A(minuend).
3. If the final carry over of the sum is 1, then it is dropped and 1 is added to the result.
4. If there is no carry over, then 15's complement of the sum is the final result and it is negative.


Here A = b06, B = c7c.
Find A - B = ? using 15's complement
First find 15's complement of B = c7c

Note : 15's complement of a number is obtained by subtracting all bits from FFF.
15's complement of c7c is
FFF
-c7c

F8F


Now Add this 15's complement of B to A

1
b06
+F8F

F95

Hints : (Move mouse over the steps for detail calculation highlight)

Step-1
`=6+F`
`=6+15`
`=21`
`=16xx1+5`
`=15_16`
`:.` Sum`=5` and carry`=1`
Step-2
`=1+0+8`
`=1+0+8`
`=9`
`=16xx0+9`
`=9_16`
`:.` Sum`=9`
Step-3
`=b+F`
`=0+15`
`=15`
`=16xx0+15`
`=F_16`
`:.` Sum`=F`



Here there is no carry, answer is - (15's complement of the sum obtained F95)

Note : 15's complement of a number is obtained by subtracting all bits from FFF.
15's complement of F95 is
FFF
-F95

06A

So answer is -06A





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