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Find 16's complement subtraction B06-C7C

Solution:
Your problem `->` 16's complement subtraction B06-C7C


16's complement subtraction steps :

1. At first, find 16's complement of the B(subtrahend).
2. Then add it to the A(minuend).
3. If the final carry over of the sum is 1, then it is dropped and the result is positive.
4. If there is no carry over, then 16's complement of the sum is the final result and it is negative.


Here A = b06, B = c7c.
Find A - B = ? using 16's complement
First find 16's complement of B = c7c

Note : 16's complement of a number is 1 added to it's 15's complement number.
15's complement of c7c is
FFF
-c7c

F8F


Now add 1 : F8F + 1 = F90

Now Add this 16's complement of B to A

b06
+F90

F96

Hints : (Move mouse over the steps for detail calculation highlight)

Step-1
`=6+0`
`=6+0`
`=6`
`=16xx0+6`
`=6_16`
`:.` Sum`=6`
Step-2
`=0+9`
`=0+9`
`=9`
`=16xx0+9`
`=9_16`
`:.` Sum`=9`
Step-3
`=b+F`
`=0+15`
`=15`
`=16xx0+15`
`=F_16`
`:.` Sum`=F`



Here there is no carry, answer is - (16's complement of the sum obtained F96)

Note : 16's complement of a number is 1 added to it's 15's complement number.
15's complement of F96 is
FFF
-F96

069


Now add 1 : 069 + 1 = 06A
So answer is -06A





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