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 Solution A sum of money 2 times itself at compound interest in 15 years In how many years, it will become 8 times of itself ?Solution:Your problem -> A sum of money 2 times itself at compound interest in 15 years In how many years, it will become 8 times of itself ?Here Let P = X, N_1 = 15 then A = 2 XA = P (1 + R/100)^(N_1)=> 2 X = X (1 + R/100) ^ 15=> (1 + R/100) ^ 15 = 2 -> (1)After N_2 years it will become 8 times of the original sumA = P (1 + R/100)^(N_2)=> 8 X = X (1 + R/100)^(N_2)=> (1 + R/100)^(N_2) = 8 -> (2)Now, solving (1) and (2), we getN_2 = 45 yearsHence, the sum of money 8 times itself after 45 years. Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me