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Problem: Backward, 2x^3-4x+1, [2,4], x=2.1, N=4 [ Calculator, Method and examples ]

Solution:
Your problem -> Backward, 2x^3-4x+1, [2,4], x=2.1, N=4

Equation is f(x) = 2x^3-4x+1.

h = (b-a)/N

h = (4 - 2) / 4 = 0.5

The value of table for X and Y

 X Y 2 2.5 3 3.5 4 9 22.25 43 72.75 113

Newton's backward differentiation method to find solution
Newton's backward differentiation table is as follows.
 X Y(X) gradY grad^2Y grad^3Y grad^4Y 2 9 13.25 2.5 22.25 7.5 20.75 1.5 3 43 9 0 29.75 1.5 3.5 72.75 10.5 40.25 4 113

The value of x at you want to find the f(x) : x = 2.1

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