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Find Backward, 2x^3-4x+1, [2,4], x=2.1, h=0.25

Your problem `->` Backward, 2x^3-4x+1, [2,4], x=2.1, h=0.25

Equation is `f(x) = 2x^3-4x+1`.

The value of table for `X` and `Y`

X 2 `x_0=2` 2.25 `x_1=2.25` 2.5 `x_2=2.5` 2.75 `x_3=2.75` 3 `x_4=3` 3.25 `x_5=3.25` 3.5 `x_6=3.5` 3.75 `x_7=3.75` 4 `x_8=4`
Y 9 `y_0=9` 14.7812 `y_1=14.7812` 22.25 `y_2=22.25` 31.5938 `y_3=31.5938` 43 `y_4=43` 56.6562 `y_5=56.6562` 72.75 `y_6=72.75` 91.4688 `y_7=91.4688` 113 `y_8=113`

Newton's backward differentiation method to find solution

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