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Find Correlation Coefficient from regression lines 5y=9x-22,20x=9y+350

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Your problem `->` Correlation Coefficient from regression lines 5y=9x-22,20x=9y+350


`5y=9x-22`

`:.-9x+5y=-22`

`9x-5y=22`

and `20x=9y+350`

`:.20x-9y=350`

`9x-5y=22 ->(1)`

`20x-9y=350 ->(2)`

equation`(1) xx 9 =>81x-45y=198`

equation`(2) xx 5 =>100x-45y=1750`

Substracting `=>-19x=-1552`

`=>19x=1552`

`=>x=1552/19`

Putting `x=1552/19 ` in equation `(1)`, we have

`9(1552/19)-5y=22`

`=>-5y=22-(13968/19)`

`=>-5y=(418-13968)/19`

`=>-5y=-13550/19`

`=>y=2710/19`

`:. x=1552/19" and "y=2710/19`



`:. bar X = 81.6842, bar Y = 142.6316`

Suppose `5y=9x-22` is regression equation of `y` on `x`

`=> 9 x + -5 y + -22 = 0`

`=> -5 y = -9 x + 22`

`=> y = -9/-5 x + 22/-5`

`=> y = 1.8 x + -4.4`

`:. byx = 1.8`


Suppose `20x=9y+350` is regression equation of `x` on `y`






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