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 Problem: Correlation Coefficient from regression lines 5y=9x-22,20x=9y+350 [ Calculator, Method and examples ]Solution:Your problem -> Correlation Coefficient from regression lines 5y=9x-22,20x=9y+3505y=9x-22:.-9x+5y=-229x-5y=22and 20x=9y+350:.20x-9y=3509x-5y=22 ->(1)20x-9y=350 ->(2)equation(1) xx 9 =>81x-45y=198equation(2) xx 5 =>100x-45y=1750Substracting =>-19x=-1552=>19x=1552=>x=1552/19Putting x=1552/19  in equation (1), we have9(1552/19)-5y=22=>-5y=22-(13968/19)=>-5y=(418-13968)/19=>-5y=-13550/19=>y=2710/19:. x=1552/19" and "y=2710/19:. bar x = 81.6842, bar y = 142.6316Suppose 5y=9x-22 is regression equation of y on x=> 9 x + -5 y + -22 = 0=> -5 y = -9 x + 22=> y = -9/-5 x + 22/-5=> y = 1.8 x + -4.4:. byx = 1.8Suppose 20x=9y+350 is regression equation of x on y=> 20 x + -9 y + -350 = 0

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