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Find Elimination x+y+z=9,2x+y-z=0,2x+5y+7z=52

Solution:
Your problem `->` Elimination x+y+z=9,2x+y-z=0,2x+5y+7z=52


Total Equations are `3`

`x+y+z=9 -> (1)`

`2x+y-z=0 -> (2)`

`2x+5y+7z=52 -> (3)`



Select the equations `(1)` and `(2)`, and eliminate the variable `x`.

`x+y+z=9`` xx 2->````2x``+``2y``+``2z``=``18```
`2x+y-z=0`` xx 1->````2x``+``y``-``z``=``0```

```y``+``3z``=``18`` -> (4)`




Select the equations `(1)` and `(3)`, and eliminate the variable `x`.

`x+y+z=9`` xx 2->````2x``+``2y``+``2z``=``18```
`2x+5y+7z=52`` xx 1->````2x``+``5y``+``7z``=``52```

`-``3y``-``5z``=``-34`` -> (5)`




Select the equations `(4)` and `(5)`, and eliminate the variable `y`.

`y+3z=18`` xx 3->````3y``+``9z``=``54```
+
`-3y-5z=-34`` xx 1->``-``3y``-``5z``=``-34```

```4z``=``20`` -> (6)`




Now use back substitution method





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