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 Solution Find 6 arithmetic mean between 3 and 24 .Solution:Your problem -> Find 6 arithmetic mean between 3 and 24 .Let  A_1, A_2, A_3, A_4, A_5, A_6 be the 6 arithmetic mean between 3 and 24.:. 3, A_1, A_2, A_3, A_4, A_5, A_6, 24 are in AP .Here First term a = 3 and Last term b = 24Comman difference d = (b-a)/(n+1) = (24-3)/(6+1) = 21/7 = 3:. Required Arithemetic Means, A_1 = T_2 = a + d = 3 + 3 = 6A_2 = T_3 = a + 2d = 3 + 2(3) = 9A_3 = T_4 = a + 3d = 3 + 3(3) = 12A_4 = T_5 = a + 4d = 3 + 4(3) = 15A_5 = T_6 = a + 5d = 3 + 5(3) = 18A_6 = T_7 = a + 6d = 3 + 6(3) = 21 Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me