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 Solution For arithemetic progression S( 33 ) = 198 , then find f( 17 ).Solution:Your problem -> For arithemetic progression S( 33 ) = 198 , then find f( 17 ).We have given S_33 = 198 and we have to find f(17) = ?We know that, S_n = n/2 [2a + (n - 1)d]S_33 = 33/2 [2a + (33 - 1)d] = 198=> 33 [a + 16d] = 198=> a + 16d = 6 ->(1)We know that, f(n) = a + (n - 1)df(17) = a + (17 - 1)d=> f(17) = a + 16d=> f(17) = 6 (Using (1)) Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me