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 For arithemetic progression addition of 3 terms is 27 and their multiplication is 648 , then that numbers [ Calculator, Method and examples ]Solution:Your problem -> For arithemetic progression addition of 3 terms is 27 and their multiplication is 648 , then that numbersLet the terms are a-d, a, a+dAddition of this terms is 27=> (a-d) + a + (a+d) = 27=> 3 a = 27=> a = 27/3 = 9Multiplication of this terms is 648=> (a-d) × a × (a+d) = 648=> (9-d) × 9 × (9+d) = 648=> (81 - d^2) = 72=> d^2 = 9=> d = +- 3d = +3 => Required terms : 9 - 3, 9, 9 + 3 => 6, 9, 12d = -3 => Required terms : 9-(-3), 9, 9-3 => 12, 9, 6

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