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For arithemetic progression addition of 3 terms is 27 and their multiplication is 648 , then that numbers

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Your problem `->` For arithemetic progression addition of 3 terms is 27 and their multiplication is 648 , then that numbers


Let the terms are `a-d, a, a+d`

Addition of this terms is `27`

`=> (a-d) + a + (a+d) = 27`

`=> 3 a = 27`

`=> a = 27/3 = 9`


Multiplication of this terms is `648`

`=> (a-d) × a × (a+d) = 648`

`=> (9-d) × 9 × (9+d) = 648`

`=> (81 - d^2) = 72`

`=> d^2 = 9`

`=> d = +- 3`

`d = +3 =>` Required terms : `9 - 3, 9, 9 + 3 => 6, 9, 12`

`d = -3 =>` Required terms : `9-(-3), 9, 9-3 => 12, 9, 6`






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