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 Solution For arithemetic progression f( 5 ) = 56 , f( 8 ) = 86 then find f( 10 ) and S( 10 ).Solution:Your problem -> For arithemetic progression f( 5 ) = 56 , f( 8 ) = 86 then find f( 10 ) and S( 10 ).We know that, f(n) = a + (n - 1)df(5) = 56=> a + (5 - 1)d = 56=> a + 4d = 56 ->(1)f(8) = 86=> a + (8 - 1)d = 86=> a + 7d = 86 ->(2)Solving (1) and (2), we get a = 16 and d = 10We know that, f(n) = a + (n - 1)df(10) = 16 + (10 - 1)(10)= 16 + (90)= 106We know that, S_n = n/2 [2a + (n - 1)d]:. S_10 = 10/2 * [2(16) + (10 - 1)(10)]= 5 * [32 + (90)]= 5 * [122]= 610 Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me