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 Solution For given geometric progression series 3,6,12,24,48 ,... then find n such that S(n) = 3069 .Solution:Your problem -> For given geometric progression series 3,6,12,24,48 ,... then find n such that S(n) = 3069 .Here a = 3,r = 6/3 = 2We know that, S_n = a * (r^n - 1)/(r - 1)=> S_n = 3 × ((2)^n - 1) / (2 - 1)=> 3069 = 3 × ((2)^n - 1)/(1)=> 2^n - 1 = 3069 × (1) / 3=> 2^n - 1 = 1023=> 2^n = 1024=> 2^n = 2^10=> n = 10 Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me