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 Problem: For given geometric progression series 3,6,12,24,48 ,... then find n such that f(n) = 1536 . [ Calculator, Method and examples ]Solution:Your problem -> For given geometric progression series 3,6,12,24,48 ,... then find n such that f(n) = 1536 .Here a = 3,r = 6/3 = 2Let n be the term such that f(n) = 1536We know that, a_n = a × r^(n-1)=> 3 × 2^(n-1) = 1536=> 2^(n-1) = 512=> 2^(n-1) = 2^9=> n - 1 = 9=> n = 9 + 1=> n = 10

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