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Find Forward, {{0,1},{1,0},{2,1},{3,10}},x=2.1

Solution:
Your problem `->` Forward, {{0,1},{1,0},{2,1},{3,10}},x=2.1


The value of table for `X` and `Y`

X 0 `x_0=0` 1 `x_1=1` 2 `x_2=2` 3 `x_3=3`
Y 1 `y_0=1` 0 `y_1=0` 1 `y_2=1` 10 `y_3=10`


Newton's forward differentiation method to find solution





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