Home

Solve any problem
(step by step solutions)
Input table (Matrix, Statistics)
Mode :
SolutionHelp
Solution will be displayed step by step (In 2 parts)
Solution
Problem: Forward, 2x^3-4x+1, [2,4], x=2.1, h=0.25 [ Calculator, Method and examples ]

Solution:
Your problem `->` Forward, 2x^3-4x+1, [2,4], x=2.1, h=0.25


Equation is `f(x) = 2x^3-4x+1`.

The value of table for `X` and `Y`

X22.252.52.7533.253.53.754
Y914.781222.2531.59384356.656272.7591.4688113

Newton's forward differentiation method to find solution
Newton's forward differentiation table is as follows.
XY(X)`DeltaY``Delta^2Y``Delta^3Y``Delta^4Y`
29
5.7812
2.2514.78121.6875
7.46880.1875
2.522.251.8750
9.34380.1875
2.7531.59382.06250
11.40620.1875
3432.250
13.65620.1875
3.2556.65622.43750
16.09380.1875
3.572.752.6250
18.71880.1875
3.7591.46882.8125
21.5312
4113


The value of `x` at you want to find the `f(x) : x = 2.1`

`h = x_1 - x_0 = 2.25 - 2 = 0.25`






Solution provided by AtoZmath.com
Any wrong solution, solution improvement, feedback then Submit Here
Want to know about AtoZmath.com and me
  
 

 
Copyright © 2019. All rights reserved. Terms, Privacy





We use cookies to improve your experience on our site and to show you relevant advertising. By browsing this website, you agree to our use of cookies. Learn more