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Find Gauss Jacobi 7y+2x=11,3x-y=5

Solution:
Your problem `->` Gauss Jacobi 7y+2x=11,3x-y=5


Total Equations are `2`

`2x+7y=11`

`3x-y=5`


The coefficient matrix of the given system is not diagonally dominant.
Hence, we re-arrange the equations as follows, such that the elements in the coefficient matrix are diagonally dominant.
`3x-y=5`

`2x+7y=11`


From the above equations
`x=1/3(5+y)`

`y=1/7(11-2x)`

Solution steps are
`1^(st)` Approximation

`x_1=1/3[5+(0)]=1/3[5]=1.666667`

`y_1=1/7[11-2(0)]=1/7[11]=1.571429`

`2^(nd)` Approximation

`x_2=1/3[5+(1.571429)]=1/3[6.571429]=2.190476`

`y_2=1/7[11-2(1.666667)]=1/7[7.666667]=1.095238`

`3^(rd)` Approximation






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