Home

Solve any problem
(step by step solutions)
Input table (Matrix, Statistics)
Mode :
SolutionHelp
Solution
Greatest number which can divide 1354 , 1806 , 2762 leaving the same remainder 10 in each case.

Solution:
Your problem `->` Greatest number which can divide 1354 , 1806 , 2762 leaving the same remainder 10 in each case.


The number divides 1354 and leaves 10 as remainder
`:.` The number exactly divides 1354 - 10 = 1344

The number divides 1806 and leaves 10 as remainder
`:.` The number exactly divides 1806 - 10 = 1796

The number divides 2762 and leaves 10 as remainder
`:.` The number exactly divides 2762 - 10 = 2752

Now, we have to find HCF of `1344, 1796, 2752`

Find HCF of 1344,1796,2752

1. Find HCF of (1344,1796)
  
1
  
1344|
1796
 |
1344
 
2
 |
 
 |
452
|
1344
|
904
 
1
|
 
|
440
|
452
|
440
 
36
|
 
|
12
|
440
|
36 
|
|
80
|
72
 
1
|
 
|
8
|
12
|
8
 
2
|
 
|
4
|
8
|
8
|
|
0

HCF of (1344, 1796) = 4

2. Now find HCF of 4 and `3^(rd)` number 2752

  
688
  
4|
2752
 |
24  
 |
 |
35 
 |
32 
 |
 |
32
 |
32
 |
 |
0

HCF of (4, 2752) = 4

`:.` HCF of given numbers (1344,1796,2752) = 4

`:.` Required number = HCF of `1344, 1796, 2752 = 4`.






Solution provided by AtoZmath.com
Any wrong solution, solution improvement, feedback then Submit Here
Want to know about AtoZmath.com and me
  
 

Share with your friends, if solutions are helpful to you.
 
Copyright © 2019. All rights reserved. Terms, Privacy