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Find HCF (2X^2-4X),(3X^4-12X^2),(2X^5-2X^4-4X^3)

Solution:
Your problem `->` HCF (2X^2-4X),(3X^4-12X^2),(2X^5-2X^4-4X^3)


Factor of `(2x^2-4x)`

= `(2x^2-4x)`

= `2x(x-2)`

= 2 x(x - 2)

Factor of `(3x^4-12x^2)`

= `(3x^4-12x^2)`

= `3x^2(x^2-4)`

= `3x^2((x)^2-(2)^2)`

= `3x^2(x-2)(x+2)`

= 3 x2(x - 2)(x + 2)

Factor of `(2x^5-2x^4-4x^3)`

= `(2x^5-2x^4-4x^3)`

= `2x^3(x^2-x-2)`

= `2x^3(x^2+x-2x-2)`

= `2x^3(x(x+1)-2(x+1))`

= `2x^3(x+1)(x-2)`

= 2 x3(x + 1)(x - 2)


GCD = 1 x(x - 2)

LCM = 2 × 3 x3(x - 2)(x + 2)(x + 1)
LCM `= 6x^3(x-2)(x+2)(x+1)`






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