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 Problem: In a throw of two coins, the probability of getting at least one tail is [ Calculator, Method and examples ]Solution:Your problem -> In a throw of two coins, the probability of getting at least one tail isTotal number of outcomes possible when a coin is tossed=2Hence, total number of outcomes possible when 2 coins are tossed,:.n(S)=2 xx 2=4Here S = {HH, HT, TH, TT}Let E = event of getting atleast 1 tail :. E = {HT, TH, TT}:.n(E) = 3:.P(E)=(n(E))/(n(S))=3/4

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