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Problem: In a throw of two coins, the probability of getting at least one tail is [ Calculator, Method and examples ]

Solution:
Your problem `->` In a throw of two coins, the probability of getting at least one tail is


Total number of outcomes possible when a coin is tossed`=2`

Hence, total number of outcomes possible when `2` coins are tossed,

`:.n(S)=2 xx 2=4`

Here `S` = {HH, HT, TH, TT}

Let `E` = event of getting atleast `1` tail

`:.` `E` = {HT, TH, TT}

`:.n(E) = 3`

`:.P(E)=(n(E))/(n(S))=3/4`








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