Home

 Solve any problem (step by step solutions) Input table (Matrix, Statistics)
Mode :
SolutionHelp
Solution
 Prove that 2 + 5 + 10 + 17 + ... n terms = n/6 (2n^2 + 3n + 7) [ Calculator, Method and examples ]Solution:Your problem -> Prove that 2 + 5 + 10 + 17 + ... n terms = n/6 (2n^2 + 3n + 7)L.H.S. = 2 + 5 + 10 + 17 + ... n terms= sum [ 1 + n^2 ]= sum 1 + sum n^2= n + (n (n + 1) (2n + 1))/6= n/6 [ 6 + (2n^2 + 3n + 1) ]= n/6 (2n^2 + 3n + 7)= R.H.S. (Proved)

Solution provided by AtoZmath.com
Any wrong solution, solution improvement, feedback then Submit Here
Want to know about AtoZmath.com and me