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 Prove that sum [ sum (2n -3) ] = n/6 (n + 1)(2n - 5) [ Calculator, Method and examples ]Solution:Your problem -> Prove that sum [ sum (2n -3) ] = n/6 (n + 1)(2n - 5)L.H.S. = sum [ sum (2n -3) ]= sum [ sum 2n - sum 3 ]= sum [ 2 × n/2 (n + 1) -3n ]= sum [ n (n + 1) - 3n ]= sum [ n^2 + n - 3n ]= sum [ n^2 - 2n ]= sum n^2 - 2 sum n= (n (n + 1) (2n + 1))/6 - 2 * (n (n + 1))/2= (n (n + 1) [ (2n + 1) - 6 ])/6= (n (n + 1) (2n - 5))/6= R.H.S. (Proved)

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