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 Solution Two numbers are in the ratio 9 : 16 and difference of arithmetic mean and geometric mean is 1 , then find that numbersSolution:Your problem -> Two numbers are in the ratio 9 : 16 and difference of arithmetic mean and geometric mean is 1 , then find that numbersHere ratio of the two terms is 9:16.Let the two terms be 9x and 16x.Now difference of their Arithmetic mean A and Geometric mean G is 1.=> A - G = 1 (Because A > G).=> (9x + 16x)/2 - sqrt(9x × 16x) = 1.=> (25x)/2 - sqrt(144) x = 1.=> x = 2=> The required two terms are 9 × 2 and 16 × 2.=> The required two terms are 18 and 32. Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me