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 Solution Find angle between 5x+2y-11=0 and 3x-y+11=0Solution:Your problem -> angle between 5x+2y-11=0 and 3x-y+11=0We shall first of all find slopes of the lines.Slope of line-15x+2y-11=0:. 2y=-5x+11:. y=-(5x)/(2)+11/2:. m_1=-5/2Slope of line-23x-y+11=0:. y=3x+11:. m_2=3Now, tan theta = |(m_1-m_2)/(1+m_1m_2)|=|(-5/2-3)/(1+(-5/2)(3))|=|(-11/2)/(1+-15/2)|=|(-11/2)/(-13/2)|=11/13theta=40.24^circ Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me