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Find bisection method 2x^3-2x-5 [ Calculator, Method and examples ]

Solution:
Your problem -> bisection method 2x^3-2x-5

Here 2x^3-2x-5=0

Let f(x) = 2x^3-2x-5

Here
 x f(x) 0 1 2 -5 -5 7

1^(st) iteration :

Here f(1) = -5 < 0 and f(2) = 7 > 0

:. Now, Root lies between 1 and 2

x_0=(1+2)/2=1.5

f(x_0)=f(1.5)=2(1.5)^(3)-2(1.5)-5=-1.25 < 0

2^(nd) iteration :

Here f(1.5) = -1.25 < 0 and f(2) = 7 > 0

:. Now, Root lies between 1.5 and 2

x_1=(1.5+2)/2=1.75

f(x_1)=f(1.75)=2(1.75)^(3)-2(1.75)-5=2.2188 > 0

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