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Find collinear A(0,0),B(2,0),C(-4,0),D(-2,0)

Solution:
Your problem `->` collinear A(0,0),B(2,0),C(-4,0),D(-2,0)


Here `A(0,0), B(2,0), C(-4,0), D(-2,0)` are the given points


`CD^2 = (-2+4)^2 + (0-0)^2 = (2)^2 + (0)^2 = 4 + 0 = 4`

`:. CD = sqrt(4) = 2`


`DA^2 = (0+2)^2 + (0-0)^2 = (2)^2 + (0)^2 = 4 + 0 = 4`

`:. DA = sqrt(4) = 2`


`AB^2 = (2-0)^2 + (0-0)^2 = (2)^2 + (0)^2 = 4 + 0 = 4`

`:. AB = sqrt(4) = 2`


`CB^2 = (2+4)^2 + (0-0)^2 = (6)^2 + (0)^2 = 36 + 0 = 36`

`:. CB = sqrt(36) = 6`


`:. CD + DA + AB = 2+2+2=6=CB`

`:.` C,D,A,B are collinear points








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