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 Solution Find collinear A(4,1),B(-2,-3),C(6,7)Solution:Your problem -> collinear A(4,1),B(-2,-3),C(6,7)Here A(4,1), B(-2,-3), C(6,7) are the given pointsBA^2 = (4+2)^2 + (1+3)^2 = (6)^2 + (4)^2 = 36 + 16 = 52:. BA = sqrt(52) = 7.2111AC^2 = (6-4)^2 + (7-1)^2 = (2)^2 + (6)^2 = 4 + 36 = 40:. AC = sqrt(40) = 6.3246BC^2 = (6+2)^2 + (7+3)^2 = (8)^2 + (10)^2 = 64 + 100 = 164:. BC = sqrt(164) = 12.8062:. BA + AC = 7.2111+6.3246=13.5357!=12.8062=BC:. B,A,C are not collinear points Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me