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Find cot(x)+tan(x)=sec(x)csc(x)

Solution:
Your problem `->` cot(x)+tan(x)=sec(x)csc(x)


LHS `=cot(x)+tan(x)`

`=cot(x)+tan(x)`

`=(((cos(x))/(sin(x)))+((sin(x))/(cos(x))))`

`=(cos^(2)(x)+sin^(2)(x))/(sin(x)cos(x))`

`=(1)/(sin(x)cos(x))`

`=csc(x)sec(x)`

`=`RHS

`:.` Result is proved...






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