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Find find quadratic equation, roots alpha=3, beta=-4

Solution:
Your problem `->` find quadratic equation, roots alpha=3, beta=-4


Let `alpha=3` and `beta=-4`

Then, the sum of the roots `= alpha+beta=(3)+(-4)=-1`

and the product of the roots `= alpha*beta=(3)*(-4)=-12`

The equation with roots `alpha` and `beta` is given by

`x^2-(alpha+beta)x+alpha*beta=0`

`:.x^2-(-1)x+(-12)=0`

`:.x^2+x-12=0`






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