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Find for rightangle triangles AB=5 and BC=12. Find Area

Solution:
Your problem `->` for rightangle triangles AB=5 and BC=12. Find Area


`"Here one Side" = 5" and other Side" = 12" (Given)"`

`"In triangle ABC, by Pythagoras' theorem"`

`AC^2 = AB^2 + BC^2`

`AC^2 = 5^2 + 12^2`

`AC^2 = 25 + 144`

`AC^2 = 169`

`AC = 13`


`"Perimeter" = AB + BC + AC`

`=5 + 12 + 13`

`=30`


`"Here base" = 5" and height" = 12`

`"Area" = 1/2 * AB * BC`

`=1/2 * 5 * 12`

`=30`







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