Home > Geometry calculators > Coordinate Geometry > Find the equation of a line passing through point A(5,5) and parallel to the line 2x+3y+4=0

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Find line through (5,5) and parallel to 2x+3y+4=0

Your problem `->` line through (5,5) and parallel to 2x+3y+4=0

When two lines are parallel, their slopes are equal.
We shall first find the slope of line `2x+3y+4=0`


`:. 3y=-2x-4`

`:. y=-(2x)/(3)-4/3`

`:.` Slope`=-2/3` and hence slope of the line parallel to this line is also `-2/3`

The equation of a line with slope m and passing through `(x_1,y_1)` is `y-y_1=m(x-x_1)`

Putting `(5,5)` for `(x_1,y_1)` and `m=-2/3,` we get

`:. y-5=-2/3(x-5)`

`:. 3(y-5)=-2(x-5)`

`:. 3y -15=-2x +10`

`:. 2x+3y-25=0`

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