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Find mean deviation about median {{10,3},{11,12},{12,18},{13,12},{14,3}} [ Calculator, Method and examples ]

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Your problem -> mean deviation about median {{10,3},{11,12},{12,18},{13,12},{14,3}}

 x(1) f(2) cf(3) |x-M|=|x-12|(4) f*|x-M|(5)=(2)xx(4) 10 3 3 3=0+3(3)=Previous (3)+(2) 2 |x - 12|=|10-12|=2 6 6=3xx2(5)=(2)xx(4) 11 12 15 15=3+12(3)=Previous (3)+(2) 1 |x - 12|=|11-12|=1 12 12=12xx1(5)=(2)xx(4) 12 18 33 33=15+18(3)=Previous (3)+(2) 0 |x - 12|=|12-12|=0 0 0=18xx0(5)=(2)xx(4) 13 12 45 45=33+12(3)=Previous (3)+(2) 1 |x - 12|=|13-12|=1 12 12=12xx1(5)=(2)xx(4) 14 3 48 48=45+3(3)=Previous (3)+(2) 2 |x - 12|=|14-12|=2 6 6=3xx2(5)=(2)xx(4) --- --- --- --- --- -- n=48 -- -- sum f*|x-M|=36

Median :
M = value of (n/2)^(th) observation

= value of (48/2)^(th) observation

= value of 24^(th) observation

From the column of cumulative frequency cf, we find that the 24^(th) observation is 12.

Hence, the median of the data is 12.

Mean deviation of Median

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