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Find median {{10,3},{11,12},{12,18},{13,12},{14,3}}

Solution:
Your problem `->` median {{10,3},{11,12},{12,18},{13,12},{14,3}}


`x`
`(1)`
Frequency `(f)`
`(2)`
`cf`
`(5)`
103 3 `3=0+3`
`(5)=`Previous `(5)+(2)`
1112 15 `15=3+12`
`(5)=`Previous `(5)+(2)`
1218 33 `33=15+18`
`(5)=`Previous `(5)+(2)`
1312 45 `45=33+12`
`(5)=`Previous `(5)+(2)`
143 48 `48=45+3`
`(5)=`Previous `(5)+(2)`
---------
`n=48`--


Median :
M = value of `(n/2)^(th)` observation

= value of `(48/2)^(th)` observation

= value of `24^(th)` observation

From the column of cumulative frequency `cf`, we find that the `24^(th)` observation is `12`.

Hence, the median of the data is `12`.








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