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Find newton raphson method 2x^3-2x-5, x0=1

Solution:
Your problem `->` newton raphson method 2x^3-2x-5, x0=1


Here `2x^3-2x-5=0`

Let `f(x) = 2x^3-2x-5`

`:. f'(x) = 6x^(2)-2`

`x_0 = 1`


`1^(st)` iteration :

`f(x_0)=f(1)=2*1^(3)-2*1-5=-5`

`f'(x_0)=f'(1)=6*1^(2)-2=4`

`x_1 = x_0 - f(x_0)/(f'(x_0))`

`x_1 = 1 - (-5)/(4)`

`x_1 = 2.25`






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