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Find newton raphson method 2x^3-2x-5, x0=1

Your problem `->` newton raphson method 2x^3-2x-5, x0=1

Here `2x^3-2x-5=0`

Let `f(x) = 2x^3-2x-5`

`:. f'(x) = 6x^(2)-2`

`x_0 = 1`

`1^(st)` iteration :



`x_1 = x_0 - f(x_0)/(f'(x_0))`

`x_1 = 1 - (-5)/(4)`

`x_1 = 2.25`

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