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Find newton raphson method 2x^3-2x-5

Solution:
Your problem `->` newton raphson method 2x^3-2x-5


Here `2x^3-2x-5=0`

Let `f(x) = 2x^3-2x-5`

`:. f'(x) = 6x^(2)-2`

Here
`x`012
`f(x)`-5-57



Here `f(1) = -5 < 0 and f(2) = 7 > 0`

`:.` Root lies between `1` and `2`

`x_0 = (1 + 2)/2 = 1.5`






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