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 Solution Find rectangle A(1,-1),B(-2,2),C(4,8),D(7,5)Solution:Your problem -> rectangle A(1,-1),B(-2,2),C(4,8),D(7,5)Here A(1,-1), B(-2,2), C(4,8), D(7,5) are the given pointsAB^2 = (-2-1)^2 + (2+1)^2 = (-3)^2 + (3)^2 = 9 + 9 = 18CD^2 = (7-4)^2 + (5-8)^2 = (3)^2 + (-3)^2 = 9 + 9 = 18BC^2 = (4+2)^2 + (8-2)^2 = (6)^2 + (6)^2 = 36 + 36 = 72AD^2 = (7-1)^2 + (5+1)^2 = (6)^2 + (6)^2 = 36 + 36 = 72AC^2 = (4-1)^2 + (8+1)^2 = (3)^2 + (9)^2 = 9 + 81 = 90BD^2 = (7+2)^2 + (5-2)^2 = (9)^2 + (3)^2 = 81 + 9 = 90Here  AB^2=CD^2 and BC^2=AD^2:. AB=CD and BC=ADand  AC^2=BD^2:. AC=BDA quadrilateral, in which opposites sides are equal and also the diagonals are equal, is a rectangle:. ABCD is a rectangle Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me