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Find row reduction [[8,-6,2],[-6,7,-4],[2,-4,3]]

Solution:
Your problem `->` row reduction [[8,-6,2],[-6,7,-4],[2,-4,3]]


Given matrix
   
`8``-6``2`
`-6``7``-4`
`2``-4``3`


`R_2 larr R_2+(3/4)xx R_1`

 = 
`8``-6``2`
 `0` `0=-6+(3/4)xx8`
`R_2 larr R_2+(3/4)xx R_1`
 `5/2` `5/2=7+(3/4)xx-6`
`R_2 larr R_2+(3/4)xx R_1`
 `-5/2` `-5/2=-4+(3/4)xx2`
`R_2 larr R_2+(3/4)xx R_1`
`2``-4``3`


`R_3 larr R_3-(1/4)xx R_1`

 = 
`8``-6``2`
`0``5/2``-5/2`
 `0` `0=2-(1/4)xx8`
`R_3 larr R_3-(1/4)xx R_1`
 `-5/2` `-5/2=-4-(1/4)xx-6`
`R_3 larr R_3-(1/4)xx R_1`
 `5/2` `5/2=3-(1/4)xx2`
`R_3 larr R_3-(1/4)xx R_1`


`R_1 larr R_1+(12/5)xx R_2`

 = 
 `8` `8=8+(12/5)xx0`
`R_1 larr R_1+(12/5)xx R_2`
 `0` `0=-6+(12/5)xx5/2`
`R_1 larr R_1+(12/5)xx R_2`
 `-4` `-4=2+(12/5)xx-5/2`
`R_1 larr R_1+(12/5)xx R_2`
`0``5/2``-5/2`
`0``-5/2``5/2`


`R_3 larr R_3+ R_2`

 = 
`8``0``-4`
`0``5/2``-5/2`
 `0` `0=0+0`
`R_3 larr R_3+ R_2`
 `0` `0=-5/2+5/2`
`R_3 larr R_3+ R_2`
 `0` `0=5/2+-5/2`
`R_3 larr R_3+ R_2`







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