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 Find secant method 2x^3-2x-5, a=1, b=4 [ Calculator, Method and examples ]Solution:Your problem -> secant method 2x^3-2x-5, a=1, b=4Here 2x^3-2x-5=0Let f(x) = 2x^3-2x-51^(st) iteration :x_0 = 1 and x_1 = 4f(x_0) = f(1) = -5 and f(x_1) = f(4) = 115:. x_2 = x_0 - f(x_0) * (x_1 - x_0)/(f(x_1) - f(x_0))x_2 = 1 - (-5) * (4 - 1)/(115 - (-5))x_2 = 1.125:. f(x_2)=f(1.125)=2(1.125)^(3)-2(1.125)-5=-4.40232^(nd) iteration :x_1 = 4 and x_2 = 1.125f(x_1) = f(4) = 115 and f(x_2) = f(1.125) = -4.4023:. x_3 = x_1 - f(x_1) * (x_2 - x_1)/(f(x_2) - f(x_1))

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