Home > Numerical methods calculators > Secant method calculator

Solve any problem
(step by step solutions)
Input table (Matrix, Statistics)
Mode :
SolutionHelp
Solution will be displayed step by step (In 4 parts)
Solution
Find secant method 2x^3-2x-5, a=1, b=4

Solution:
Your problem `->` secant method 2x^3-2x-5, a=1, b=4


Here `2x^3-2x-5=0`

Let `f(x) = 2x^3-2x-5`


`1^(st)` iteration :

`x_0 = 1` and `x_1 = 4`

`f(x_0) = f(1) = -5` and `f(x_1) = f(4) = 115`

`:. x_2 = x_0 - f(x_0) * (x_1 - x_0) / (f(x_1) - f(x_0))`

`x_2 = 1 - (-5) xx (4 - 1)/(115 - (-5))`

`x_2 = 1.125`

`:. f(x_2)=f(1.125)=2*1.125^(3)-2*1.125-5=-4.4023`


`2^(nd)` iteration :

`x_1 = 4` and `x_2 = 1.125`

`f(x_1) = f(4) = 115` and `f(x_2) = f(1.125) = -4.4023`

`:. x_3 = x_1 - f(x_1) * (x_2 - x_1) / (f(x_2) - f(x_1))`






Solution provided by AtoZmath.com
Any wrong solution, solution improvement, feedback then Submit Here
Want to know about AtoZmath.com and me
  
 

Share with your friends
 
Copyright © 2018. All rights reserved. Terms, Privacy