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 Solution Find square A(0,0),B(2,2),C(0,4),D(-2,2)Solution:Your problem -> square A(0,0),B(2,2),C(0,4),D(-2,2)Here A(0,0), B(2,2), C(0,4), D(-2,2) are the given pointsAB^2 = (2-0)^2 + (2-0)^2 = (2)^2 + (2)^2 = 4 + 4 = 8BC^2 = (0-2)^2 + (4-2)^2 = (-2)^2 + (2)^2 = 4 + 4 = 8CD^2 = (-2-0)^2 + (2-4)^2 = (-2)^2 + (-2)^2 = 4 + 4 = 8AD^2 = (-2-0)^2 + (2-0)^2 = (-2)^2 + (2)^2 = 4 + 4 = 8AC^2 = (0-0)^2 + (4-0)^2 = (0)^2 + (4)^2 = 0 + 16 = 16BD^2 = (-2-2)^2 + (2-2)^2 = (-4)^2 + (0)^2 = 16 + 0 = 16Here  AB^2=BC^2=CD^2=AD^2:. AB=BC=CD=ADand  AC^2=BD^2:. AC=BDA quadrilateral, in which all sides are equal and also the diagonals are equal, is a square:. ABCD is a square Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me