


Method and examples


HCF_LCM 



Problem 4 of 11 


4. Find the least number which when divided by leaves the same remainder in each case.










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HCF_LCM 
4. Find the least number which when divided by 6,7, 8, 9,12 leaves the same remainder 2 in each case.
`"Required number" = ( "LCM of " 6,7,8,9,12 ) + 2 = 504 + 2 = 506`.
2  6   7   8   9   12  2  3   7   4   9   6  2  3   7   2   9   3  3  3   7   1   9   3  3  1   7   1   3   1  7  1   7   1   1   1   1   1   1   1   1 
LCM of 6,7,8,9,12 = 2 × 2 × 2 × 3 × 3 × 7 = 504





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