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Method and examples
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Geometric Progression |
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Problem 7 of 23 |
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7. For geometric progression of terms is and th term is times then the th term.
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Solution
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Solution provided by AtoZmath.com
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This is demo example. Please click on Find button and solution will be displayed in Solution tab (step by step)
| Geometric Progression |
7. For geometric progression multiplication of 5 terms is 1 and 5 th term is 81 times then the 1 th term.
Let the terms are `(a / r^2) , (a / r) , a , (a × r) , (a × r^2)`
Multiplication : `(a / r^2) * (a / r) * a * (a × r) * (a × r^2) = 1`
`=> a^5 = 1`
`=> a = 1`
Now `5^(th)` term is `81` times than the `1^(st)` term
`=> (a × r^2) = 81 (a / r^2)`
`=> r^4 = 81`
`=> r = 3`
Now, `a = 1` and `r = 3 => (1 / 3^2) , (1 / 3) , 1 , (1 × 3) , (1 × 3^2) => 0.1111 , 0.3333 , 1 , 3 , 9`
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