Home > Numerical methods calculators > Five point Forward difference, Central difference formula numerical differentiation example

4. Five point Forward difference, Central difference formula numerical differentiation example ( Enter your problem )
  1. Formula & Example-1 (table data)
  2. Example-2 (table data)
  3. Example-3 (`f(x)=cosx`)
  4. Example-4 (`f(x)=2x^3+x^2-4`)
  5. Example-5 (`f(x)=xlnx`)
  6. Example-6 (`f(x)=sinx`)
Other related methods
  1. Two point Forward, Backward, Central difference formula
  2. Three point Forward, Backward, Central difference formula
  3. Four point Forward, Backward, Central difference formula
  4. Five point Forward, Central difference formula

3. Four point Forward, Backward, Central difference formula
(Previous method)
2. Example-2 (table data)
(Next example)

1. Formula & Example-1 (table data)





Formula
1. Five-point FDF (Forward difference formula)
`f^'(x)=1/(12h)[-25f(x)+48f(x+h)-36f(x+2h)+16f(x+3h)-3f(x+4h)]`
2. Five-point CDF (Central difference formula)
`f^'(x)=1/(12h)[f(x-2h)-8f(x-h)+8f(x+h)-f(x+2h)]`
3. Five-point CDF (Central difference formula) for second derivatives
`f^('')(x)=1/(12h^2)[-f(x-2h)+16f(x-h)-30f(x)+16f(x+h)-f(x+2h)]`

Examples
Using Five point Forward difference, Backward difference, Central difference formula numerical differentiation to find solution
x11.051.101.151.201.251.30
f(x)11.024701.048811.072381.095451.118031.14018

`f^'(1.10) and f^('')(1.10)`


Solution:
The value of table for `x` and `y`

x11.051.11.151.21.251.3
y11.02471.04881.07241.09541.1181.1402

Five-point FDF (Forward difference formula)
`f^'(x)=1/(12h)[-25f(x)+48f(x+h)-36f(x+2h)+16f(x+3h)-3f(x+4h)]`

`f^'(1.10)=1/(12*0.05)[-25f(1.10)+48f(1.10+0.05)-36f(1.10+2*0.05)+16f(1.10+3*0.05)-3f(1.10+4*0.05)]`

`f^'(1.10)=1/(0.6)[-25f(1.10)+48f(1.15)-36f(1.2)+16f(1.25)-3f(1.3)]`

`f^'(1.10)=1/(0.6)[-25(1.0488)+48(1.0724)-36(1.0954)+16(1.118)-3(1.1402)]`

`f^'(1.10)=0.4762`



Five-point CDF (Central difference formula)
`f^'(x)=1/(12h)[f(x-2h)-8f(x-h)+8f(x+h)-f(x+2h)]`

`f^'(1.10)=1/(12*0.05)[f(1.10-2*0.05)-8f(1.10-0.05)+8f(1.10+0.05)-f(1.10+2*0.05)]`

`f^'(1.10)=1/0.6[f(1)-8f(1.05)+8f(1.15)-f(1.2)]`

`f^'(1.10)=1/0.6[1-8(1.0247)+8(1.0724)-1.0954]`

`f^'(1.10)=0.4767`



Five-point CDF (Central difference formula) for second derivatives
`f^('')(x)=1/(12h^2)[-f(x-2h)+16f(x-h)-30f(x)+16f(x+h)-f(x+2h)]`

`f^('')(1.10)=1/(12*(0.05)^2)[-f(1.10-2*0.05)+16f(1.10-0.05)-30f(1.10)+16f(1.10+0.05)-f(1.10+2*0.05)]`

`f^('')(1.10)=1/0.03[-f(1)+16f(1.05)-30f(1.10)+16f(1.15)-f(1.2)]`

`f^('')(1.10)=1/0.03[-1+16(1.0247)-30(1.0488)+16(1.0724)-1.0954]`

`f^('')(1.10)=-0.2157`


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3. Four point Forward, Backward, Central difference formula
(Previous method)
2. Example-2 (table data)
(Next example)





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