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 6. Find the equation of a line using slope, point, X-intercept, Y-intercept example ( Enter your problem ) 1. Examples 1. Find the equation of a line having slope =1/2 and passing through point A(5,4)Solution:The equation of a line with slope m and passing through (x_1,y_1) is y-y_1=m(x-x_1)Putting (5,4) for (x_1,y_1) and m=1/2, we get:. y-4=1/2(x-5):. 2(y-4)=(x-5):. 2y -8=x -5:. x-2y+3=0 2. Find the equation of a line passing through two points A(3,5) and B(6,4)Solution:Here A(3,5), B(6,4) are the given points:. x_1=3, y_1=5, x_2=6, y_2=4The equation of a line AB is(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1):. (y-5)/(4-5)=(x-3)/(6-3):. (y-5)/(-1)=(x-3)/(3):. 3(y-5)=-(x-3):. 3y -15=-x +3:. x+3y-18=0 3. Find the equation of a line having slope =2 and y intercept =3Solution:Equation of a line with slope m and intercept c on Y-axis is y=mx+cHere m=2 and c=3y=2x+3:. 2x-y+3=0 4. Find the equation of a line having X-intercept =3 and Y-intercept =-5Solution:Here intercept on X-axis a=3 and Y-intercept b=-5Equation of a line isx/a+y/b=1:. x/(3)+y/(-5)=1:. (x)/(3)-(y)/(5)=1:. 5x-3y=15 This material is intended as a summary. Use your textbook for detail explanation.Any bug, improvement, feedback then Submit Here