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Method and examples
Method
Solving systems of linear equations using
Gauss Jacobi method
Enter Equations line by line like
2x+5y=16
3x+y=11
Or 2, 5, 16
3, 1, 11
Initial gauss / Start value = ( )
Convert to Diagonnay Dominant Equation (if required) =
Mode =
Decimal Place =
Click here to Find the value of h,k for which the system of equations has a Unique or Infinite or no solution calculator
SolutionHelp
Solving systems of linear equations using Gauss Jacobi method calculator
1. 2x+y+z=5,3x+5y+2z=15,2x+y+4z=8
2. 2x+5y=16,3x+y=11
3. 2x+5y=21,x+2y=8
4. 2x+y=8,x+2y=1
5. 2x+3y-z=5,3x+2y+z=10,x-5y+3z=0
6. x+y+z=3,2x-y-z=3,x-y+z=9
7. x+y+z=7,x+2y+2z=13,x+3y+z=13
8. 2x-y+3z=1,-3x+4y-5z=0,x+3y-6z=0


Example
1. Solve Equations 2x+5y=21,x+2y=8 using Gauss Jacobi method

Solution:
Total Equations are 2

2x+5y=21

x+2y=8


From the above equations
x_(k+1)=1/2(21-5y_(k))

y_(k+1)=1/2(8-x_(k))

Initial gauss (x,y) = (0,0)

Solution steps are
1^(st) Approximation

x_1=1/2[21-5(0)]=1/2[21]=10.5

y_1=1/2[8-(0)]=1/2[8]=4

2^(nd) Approximation

x_2=1/2[21-5(4)]=1/2[1]=0.5

y_2=1/2[8-(10.5)]=1/2[-2.5]=-1.25

3^(rd) Approximation

x_3=1/2[21-5(-1.25)]=1/2[27.25]=13.625

y_3=1/2[8-(0.5)]=1/2[7.5]=3.75

4^(th) Approximation

x_4=1/2[21-5(3.75)]=1/2[2.25]=1.125

y_4=1/2[8-(13.625)]=1/2[-5.625]=-2.8125

5^(th) Approximation

x_5=1/2[21-5(-2.8125)]=1/2[35.0625]=17.5312

y_5=1/2[8-(1.125)]=1/2[6.875]=3.4375

6^(th) Approximation

x_6=1/2[21-5(3.4375)]=1/2[3.8125]=1.9062

y_6=1/2[8-(17.5312)]=1/2[-9.5312]=-4.7656

7^(th) Approximation

x_7=1/2[21-5(-4.7656)]=1/2[44.8281]=22.4141

y_7=1/2[8-(1.9062)]=1/2[6.0938]=3.0469


Equations are Divergent...
Intertions are tabulated as below
Iterationxy
110.54
20.5-1.25
313.6253.75
41.125-2.8125
517.53123.4375
61.9062-4.7656
722.41413.0469




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