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Solution
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Solution provided by AtoZmath.com
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t-test calculator
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1. Parametric test - t-test for the following data 3,11,17,28,34 5,8,13,19,28, Significance Level `alpha=0.05` and One-tailed test
2. Parametric test - t-test for the following data 2.9,3.1,3.5,3.4,3.0,4.0,3.7,3.0,4.0,4.0 2.7,2.8,3.0,3.5,3.7,3.2,3.0,3.1,2.9,2.8, Significance Level `alpha=0.05` and One-tailed test
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Example1. Parametric test - t-test for the following data 3,11,17,28,34 5,8,13,19,28, Significance Level `alpha=0.05` and One-tailed testSolution:Step-1: Take the hypothesis Null Hypothesis `H_0` : There is no significant differentiating between samples Alternative Hypothesis `H_1` : There is significant differentiating between samples Step-2: Calculate `S_1^2,S_2^2` `bar x_1=18.6` and Variance `S_(1)^2=157.3` for `3,11,17,28,34``x` | `dx = x - A = x - 19` | `dx^2` | 3 | -16 | 256 | 11 | -8 | 64 | 17 | -2 | 4 | 28 | 9 | 81 | 34 | 15 | 225 | --- | --- | --- | `sum x=93` | `sum (dx)=-2` | `sum (dx)^2=630` |
Mean `bar x = (sum x)/n` `=(3 + 11 + 17 + 28 + 34)/5` `=93/5` `=18.6` `bar x = 18.6` is not an integer, use assumed mean method `A = 19`
Sample Variance `S^2 = (sum dx^2 - (sum dx)^2/n)/(n-1)` `=(630 - (-2)^2/5)/4` `=(630 - 0.8)/4` `=629.2/4` `=157.3`
`bar x_2=14.6` and Variance `S_(2)^2=84.3` for `5,8,13,19,28``x` | `dx = x - A = x - 15` | `dx^2` | 5 | -10 | 100 | 8 | -7 | 49 | 13 | -2 | 4 | 19 | 4 | 16 | 28 | 13 | 169 | --- | --- | --- | `sum x=73` | `sum (dx)=-2` | `sum (dx)^2=338` |
Mean `bar x = (sum x)/n` `=(5 + 8 + 13 + 19 + 28)/5` `=73/5` `=14.6` `bar x = 14.6` is not an integer, use assumed mean method `A = 15`
Sample Variance `S^2 = (sum dx^2 - (sum dx)^2/n)/(n-1)` `=(338 - (-2)^2/5)/4` `=(338 - 0.8)/4` `=337.2/4` `=84.3`
Step-3: Calculate `t` `t=|x_1-x_2|/sqrt((S_1^2)/n_1 + (S_2^2)/n_2)` `=|18.6-14.6|/sqrt(157.3/5 + 84.3/5)` `=|4|/sqrt(31.46 + 16.86)` `=|4|/sqrt(48.32)` `=|4|/6.9513` `=0.5754` Step-4:Degree of freedom `= n_1 + n_2 - 2 = 5+5-2=8` Step-5:`df=8,t_(0.05)=1.8595` As calculated `t=0.5754 < 1.8595` So, `H_0` is accepted, Hence there is no significant differentiating between samples
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