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Numerical differentiation using Stirling's formula
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Method
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 x =
  1. x7.477.487.497.507.517.527.53
    f(x)0.1930.1950.1980.2010.2030.2060.208
    and x=7.5
  2. x0300600900120015001800
    f(x)135149157183201205193
    and x=900
  3. x0.00.10.20.30.4
    f(x)1.00000.99750.99000.97760.8604
    and x=0.2
  4. x1.41.61.82.02.2
    f(x)4.05524.95306.04967.38919.0250
    and x=0.8
f(x) =
x1 = and x2 =
 x =
Step value (h) =  OR  Interval (N) =
=
  1. `f(x)=2x^3-4x+1`
    x1 = 2 and x2 = 4
    x = 3
    Interval N = 5
  2. `f(x)=x^3-x+1`
    x1 = 2 and x2 = 4
    x = 3
    Interval N = 5
  3. `f(x)=x^3+x+2`
    x1 = 2 and x2 = 4
    x = 3
    Interval N = 5
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