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Method and examples
Numerical interpolation using Bessel's formula
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x =
Option :
  1. X20242832
    f(x)2854316235443992
    and x=25
  2. X20242832
    f(x)24323540
    and x=25
  3. X2.53.03.54.04.55.0
    f(x)24.14522.04320.22518.64417.26216.047
    and x=3.75
  4. X1011121314
    f(x)20.984822.981624.978126.974328.9702
    and x=12.3
f(x) =
x1 = and x2 =
 x =
Step value (h) =  OR  Inverval (N) =
=
Option :
  1. `f(x)=2x^3-4x+1`
    x1 = 2 and x2 = 4
    x = 3.8
    Step value (h) = 1
    or N = 5
  2. `f(x)=2x^3-4x+1`
    x1 = 2 and x2 = 4
    x = 2.1
    Step value (h) = 1
    or N = 8
  3. `f(x)=x^3-x+1`
    x1 = 2 and x2 = 4
    x = 3.8
    Step value (h) = 1
    or N = 5
  4. `f(x)=x^3-x+1`
    x1 = 2 and x2 = 4
    x = 2.1
    Step value (h) = 1
    or N = 8
  5. `f(x)=x^3+x+2`
    x1 = 2 and x2 = 4
    x = 3.8
    Step value (h) = 1
    or N = 5
  6. `f(x)=x^3+x+2`
    x1 = 2 and x2 = 4
    x = 2.1
    Step value (h) = 1
    or N = 8
  7. `f(x)=sin(x)`
    x1 = 0 and x2 = 1.57
    x = 2
    Step value (h) = 1
    or N = 8
  8. `f(x)=cos(x)`
    x1 = 0 and x2 = 1.57
    x = 2
    Step value (h) = 1
    or N = 8
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